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2/3a^2=6
We move all terms to the left:
2/3a^2-(6)=0
Domain of the equation: 3a^2!=0We multiply all the terms by the denominator
a^2!=0/3
a^2!=√0
a!=0
a∈R
-6*3a^2+2=0
Wy multiply elements
-18a^2+2=0
a = -18; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-18)·2
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12}{2*-18}=\frac{-12}{-36} =1/3 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12}{2*-18}=\frac{12}{-36} =-1/3 $
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